Question

(y-3)(y-5)-2y(y-1)=(y-3)(y-2)+6-2y2

Answer 1

Respuesta:

y=3

Explicación paso a paso:

(y-3)(y-5)-2y(y-1)=(y-3)(y-2)+6-2y2

$y^{2} -5y-3y+15-2y^{2} +2y=y^{2}-2y-3y+6+6-2y^{2}$

$-y^{2}-6y+15=-y^{2}-5y+12\\\\-y^{2}+y^{2}-6y+5y+15-12=0$

-y+3=0

y=3