Question

Cuanto calor se necesita para elevar la temperatura de 38 Oz de mercurio de 18°f a 212°f

Answer 1

Respuesta:

Ce Hg = 0.033 cal/g ºC

m = 200 g

T2 = 100 ºC

T1 = 20 ºC

Q = m Ce (T2 - T1)

Q = 200 g . 0.033 cal/gºC ( 100 - 20)ºC

Q = 6.6 calorias · 80

Q = 528 calorias

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m = 200 / 1000 = 0.200 Kg

Ce Hg = 138 J/Kg ºC

Q = 0.200 Kg · 138 Joule/Kg ºC ( 100 - 20)ºC

Q = 27.6 Joules · 80

Q = 2208Joules