Question

logaritmos porfaaaa!!!!​

Answer 1

Respuesta:

Explicación paso a paso:

Answer 2

Respuesta:

Explicación paso a paso:

Datos:

LogA = -1

LogB = 2

Desarrollamos:

a) Log (A³*√B)

= LogA³ + Log√B

= 3*LogA + Log(B)^(1/2)

= 3*LogA + (1/2)*Log(B)

= 3*(-1) + (1/2)*(2)

= -3 + 1

= -2

a) Log[√(A*B)³ ]

= Log[(A*B)^(3/2)]

= Log[(A*B)^(3/2)]

= (3/2)*Log(A*B)

= (3/2)*(LogA + LogB)

= (3/2)*(-3 + 2)

= (3/2)*(-1)

= -(3/2)