Question

alguien por favor ayudaaa el primer ejercicio y el segundo con desarrollo

no respondas si no sabes. gracias ​

Answer 1

Respuesta:

A) 3(1)(2) = 6

B) 24(1/2)²(1/3)³(1/4) =24(1/4)(1/27)(1/4) = 6×(1/27)(1/4) = (6/27)(1/4) = 6/108 = 1/18.

C) 1/12(3)³(1/3)(1/4)² = 1/12 × 27 × 1/3 × 1/16 = 1/4 × 3 × 1 × 1/16 = 3/64

D) (5)² - 2(5)(4) + (4)² = 25 - 40 + 16 = 41 - 40 = 1

E) (1/4)/(1/2) - 3/(1/4) + 2 = (2/4) - 12 + 2 = (2-48)/4 + 2 = (-46/4) + 2 = (-46+8)/4 = -38/4 = -19/2

A pedido del estudiante.

[√(1+3)/2 + √(6×2/3)/2] ÷ (3+4)×√(1/4)

[√4/2 + √(2×2)/2] ÷ 7×1/2

[2/2 + 2/2] ÷ 7/2

1 + 1 ÷ 7/2

2 ÷ (7/2) = 4/7

[√(3²+4²)/1 ÷ 2/√4] ×1/2

[√25/1 ÷ 2/2] ×1/2

5 ÷ 1 × 1/2

5×1/2 = 5/2