Respuestas
Explicación paso a paso:
(x4+12x3-64x2)≥0
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "x2" was replaced by "x^2". 2 more similar replacement(s).
Step by step solution :
Step 1 :
Equation at the end of step 1 :
((x4) + (12 • (x3))) - 26x2 ≥ 0
Step 2 :
Equation at the end of step 2 :
((x4) + (22•3x3)) - 26x2 ≥ 0
Step 3 :
Step 4 :
Pulling out like terms :
4.1 Pull out like factors :
x4 + 12x3 - 64x2 = x2 • (x2 + 12x - 64)
Trying to factor by splitting the middle term
4.2 Factoring x2 + 12x - 64
The first term is, x2 its coefficient is 1 .
The middle term is, +12x its coefficient is 12 .
The last term, "the constant", is -64
Step-1 : Multiply the coefficient of the first term by the constant 1 • -64 = -64 Step-2 : Find two factors of -64 whose sum equals the coefficient of the middle term, which is 12 .
-64 + 1 = -63
-32 + 2 = -30
-16 + 4 = -12
-8 + 8 = 0
-4 + 16 = 12 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -4 and 16
x2 - 4x + 16x - 64
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (x-4)
Add up the last 2 terms, pulling out common factors :
16 • (x-4)
Step-5 : Add up the four terms of step 4 :
(x+16) • (x-4)
Which is the desired factorization
Equation at the end of step 4 :
x2 • (x + 16) • (x - 4) ≥ 0
Step 5 :
Run Time Error 78: Non Linear Inequality not implemented yet
Program Terminated
Tiger was not able to solve for your input:(x4+12x3-64x2)>=0
espero que te sirva