Question

Calcule la presión en Torr de 0,652 moles de Oxígeno gaseoso que ocupa un cilindro de 10 L a 30°C

Answer 1

Respuesta:

P  V  =  n x R  x  T

T = 30 + 273 = 303 K

V = 10 L

n = 0.652 mol

R = 0.0821 (L atm / mol K )

P = n x R x T

       ````````````

            V

P = 0.652 mol  x  0.0821 (L atm / mol K ) x 303 K

       ``````````````````````````````````````````````````````````````

                               10 L

P = 1.62  atm

  760 torr -------  1 atm

         x      -------  1.62 atm

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