Question

esto.................................​

Answer 1

Respuesta:

4

Explicación paso a paso:

E = $\frac{\sqrt{5+\sqrt{24} } }{\sqrt{3} +\sqrt{2} } +\frac{\sqrt{5-\sqrt{24} } }{\sqrt{3}-\sqrt{2} }$  ; a toda la ecuacion lo elevamos al cuadrado, entonces:

$E^{2} = ( \frac{\sqrt{5+\sqrt{24} } }{\sqrt{3} +\sqrt{2} } +\frac{\sqrt{5-\sqrt{24} } }{\sqrt{3}-\sqrt{2} })^{2}$ ; $(a+b)^{2} = a^{2} +2ab+b^{2}$

                              $(a+b)(a-b)=a^{2} -b^{2}$

                                             ↓

$E^{2} = (\frac{\sqrt{5+\sqrt{24} } }{\sqrt{3} +\sqrt{2} })^{2} +2(\frac{\sqrt{5+\sqrt{24} } }{\sqrt{3}+\sqrt{2} })(\frac{\sqrt{5-\sqrt{24} } }{\sqrt{3-\sqrt{2} } } ) +(\frac{\sqrt{5-\sqrt{24} } }{\sqrt{3}-\sqrt{2} })^{2}$

$E^{2} =\frac{5+\sqrt{24} }{(\sqrt{3}+\sqrt{2} )^{2} } +2\frac{\sqrt{5^{2-(\sqrt{24}^{2} )} } }{(\sqrt{3}+\sqrt{2} )(\sqrt{3}-\sqrt{2} )} +\frac{\sqr{5-\sqrt{24} } }{(\sqrt{3}-\sqrt{2} )^{2} } }$

$E^{2} = \frac{5+\sqrt{24} }{3+2\sqrt{3}\sqrt{2}+2 } +2(\frac{\sqrt{25-24} }{(\sqrt{3} )^{2} -(\sqrt{2} )^{2} } )+\frac{5-\sqrt{24} }{3-2\sqrt{3}\sqrt{2}+2 }$

     $\sqrt{24} = 2\sqrt{6}$            $\sqrt{24} = 2\sqrt{6}$  (expresarlo de otra forma)

               ↓                        ↓

$E^{2} =\frac{5+2\sqrt{6} }{5+2\sqrt{6} } +2(\frac{\sqrt{1} }{3-2} )+\frac{5-2\sqrt{6} }{5-2\sqrt{6} }$

$E^{2} =1+2(\frac{1}{1} )+1} }$

$E^{2} =1+2+1$

$E^{2} =4$

Answer 2

Respuesta:

al ojo papu saleE= 2 piden E²=4

Explicación paso a paso:

propiedad

√(3+2+2√2.3) = √3+√2

igual para

√(3+2-2√3.2) =√3-√2

E=1+1

E=2

E²=4

chao