Question

determina el porcentaje de carbono presente en el siguiente compuesto: Dióxido de carbono,CO2

Answer 1

Respuesta:

a) C3H8

Mm

C: 3 x 12 = 36 g/mol

H: 8 x 1 = 8 g/mol

``````````````````````````````

     Mm = 44 g/mol

% C

 

44 g ----- 100 %

36 g -----     x

     x = 81.81 % C

b.  H-COOH

Mm

C: 1 x 12 = 12 g/mol

H: 2 x 1 = 2 g/mol

O: 2 x 16 = 32 g/mol

``````````````````````````````

    Mm = 46 g/mol

% Carbono

46 g ---- 100 %

12 g ----   x

    x = 26.07 % C

c. CO2

C: 1 x 12 = 12 g/mol

O: 2 x 16 = 32 g/mol

````````````````````````````

        Mm = 44 g/mol

%C

44 g ---- 100 %

12 g ----     x

      x = 27.27 % C

d.  CO

C: 1 x 12 = 12 g/mol

O: 1 x 16 = 16 g/mol

````````````````````````````

        Mm =  28 g/mol

%C

28 g ---- 100 %

12 g ----     x

      x = 42.86 % C

e.  C2H2

C: 2 x 12 = 24 g/mol

H: 2 x  1  = 2 g/mol

````````````````````````````

        Mm = 26 g/mol

%C

26 g ---- 100 %

24 g ----     x

      x = 92.30 % C

Explicación:

espero que te sirva xd