Question

f(x)= x^2√x-1 son derivadas nececitoa ayuda

Answer 1

Explicación paso a paso:

$f'(x) = 2x(\sqrt[]{x-1})+\frac{1}{2\sqrt{x-1} }(1)(x^{2} )\\ f'(x) = 2x\sqrt{x-1}+\frac{x^{2} }{2\sqrt{x-1} }\\ f'(x) = \frac{4x(x-1)+(x^{2} )}{2\sqrt{x-1} }\\ f'(x) = \frac{4x^{2}-4x+x^{2} }{2\sqrt{x-1} }\\ f'(x) = \frac{5x^{2}-4x }{2\sqrt{x-1} }$