Question

$B=\frac{\sqrt[4]{32} }{\sqrt[4]{2} }- \frac{\sqrt[3]{81} }{\sqrt[3]{3} }- \frac{\sqrt{8} }{\sqrt{2} }$

Answer 1

Respuesta:

-3

Explicación paso a paso:

$\frac{2\sqrt[4]{2} }{\sqrt[4]{2} } -\frac{3\sqrt[3]{3} }{\sqrt[3]{3} } -\frac{2\sqrt{2} }{\sqrt{2} } \\2-3-2=-3$