Question

A ver quien le hace a esta Ec.Cuadrática (con desarrollo) ​

Answer 1

Resolución de ecuación de segundo grado

$\boxed {\bold { x^{2} + 3 \ . (-\frac {53}{13})x -10 = 0}}$

$\boxed {\bold { x^{2} - 3 \ . (\frac {53}{13})x -10 = 0}}$

$\boxed {\bold { x^{2} + \frac {-3\ .\ 53}{13}x -10 = 0}}$

$\boxed {\bold { x^{2} + \frac {-159}{13}x -10 = 0}}$

$\boxed {\bold { x^{2} - \frac {159x}{13} -10 = 0}}$

$\boxed {\bold { 13x^{2} +13 (-\frac {159x}{13}) +13\ .-10 = 0}}$

$\boxed {\bold{13x^{2} -159x -130 = 0}}$

Empleamos la formula cuadrática

Donde a = 13, b = -159 y c = -130

$\boxed {\bold {- b \pm\frac{\sqrt{b^{2}-4ac } }{2a} }}$

$\boxed {\bold {x = 159 \pm\frac{\sqrt{(-159)^{2}-4\ . (13\ .-130)} }{2\ .13} }}$

$\boxed {\bold {x = 159 \pm\frac{\sqrt {{25281}-4\ . -1960} }{26} }}$

$\boxed {\bold {x = 159 \pm\frac{\sqrt {{25281} + 6760} }{26} }}$

$\boxed {\bold {x = 159 \pm\frac{\sqrt {32041 } }{26} }}$

$\boxed {\bold {x = 159 \pm\frac{\sqrt {179^{2} } }{26} }}$

$\boxed {\bold {x = \frac{159 \pm 179}{26} }}$

$\boxed {\bold {x_{1} = 13}}$  

$\boxed { \bold {x = _{2} - \frac{10}{13} }}$