Question

Sabiendo que log2=0,30103 y log3=0,47712, calcula:
a)log72
b) log16
c)log 0,3
d) log 0,48
e) log 48/9
f) log (raiz) 9/5

Answer 1

a)

$= log(72) \\ = log( {2}^{3} \times {3}^{2} ) \\ = 3 log(2) + 2 log(3) \\ = 1.90848$

b)

$= log(16) \\ = log( {2}^{4} ) \\ = 4 log(2) \\ = 1.20412$

c)

$= log(0.3) \\ = log( \frac{3}{10} ) \\ = log(3) - log( 10) \\ = log(3) - 1 \\ = - 0.52288$

d)

$= log(0.48) \\ = log( \frac{ {2}^{4} \times 3}{10} ) \\ = 4 log(2) + log(3) - log(10) \\ = 4 log(2) + log(3) - 1 \\ = 0.68124$

e)

$= log( \frac{48}{9} ) \\ = log( \frac{ {2}^{4} }{3} ) \\ = 4 log(2) - log(3) \\ = 0.727$

f) Faltan datos.

Answer 2

Respuesta:

dame corona