Question

P(x-3)=2x^2-5x
hallar: p(2)+P(0)​

Answer 1

Respuesta:

28

Explicación paso a paso:

P(x-3) = 2x² - 5x

P(x-3+3) = 2(x+3)²-5(x+3)

P(x+0) = 2(x²+6x+9)-5x-15

P(x) = 2x²+12x+18-5x-15

P(x) = 2x²+7x+3

P(2) = 2(2)²+7(2)+3

P(2) = 2(4)+14+3

P(2) = 8+14+3

P(2) = 25

P(0) = 2(0)²+7(0) + 3

P(0) = 3

Hallar :

P(2)+P(0) = 25+3 = 28