Question

tan^2x - tanx = 6 con 0°<_ x <_ 180°

Answer 1

$\tan^2 x -\tan x - 6 = 0\\ \\ (\tan x -3)(\tan x+2)=0\\ \\ \tan x=3 \vee \tan x = -2\\ \\ \boxed{x=\arctan 3\vee x=\pi -\arctan 2}$