Question

pH de [OH-] = 1 x 10-6

Answer 1

Respuesta: Porcentaje protonado = [(1,1 x ÍO^^OH] x 100 = 0,92%. ... pH = -íog (7,5 x 10-6) = 5,12 10.14B F" + H^O - HF + OH"; K (HF) = 3,5 x 10^; Kb(F-~) = (1,0 ... 0,045 moles--1; [NH2CH2C02-] = 1,7 x 1 0-10 moles-L-1; [OH-] = 2,2 x 1 0-1 3 moles"- L-1.

Explicación:

Porcentaje protonado = [(1,1 x ÍO^^OH] x 100 = 0,92%. ... pH = -íog (7,5 x 10-6) = 5,12 10.14B F" + H^O - HF + OH"; K (HF) = 3,5 x 10^; Kb(F-~) = (1,0 ... 0,045 moles--1; [NH2CH2C02-] = 1,7 x 1 0-10 moles-L-1; [OH-] = 2,2 x 1 0-1 3 moles"- L-1.