Question

Alguien me puede resolver esto?por favor​

Answer 1

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$\sqrt[3]{ \frac{1}{2} x - 1. \frac{}{6} } + 0.6 = \sqrt{0.01} \\ \sqrt[3]{ \frac{x}{2} - \frac{5}{3} } + \frac{6}{10} = \sqrt{ \frac{1}{100} } \\ \sqrt[3]{ \frac{3x - 10}{6} } = \frac{1}{10} - \frac{6}{10} \\ \sqrt[3]{ \frac{3x - 10}{6} } = - \frac{5}{10} \\ \frac{3x - 10}{6} = {( - \frac{1}{2}) }^{3} \\ \frac{3x - 10}{6} = - \frac{1}{8} \\ 12x - 40 = - 3 \\ 12x = 37 \\ x = \frac{37}{12}$