Question

El aérea de un rombo cuyo lado mide 8cm y su diagonal menor mide 6cm

Answer 1

Respuesta:

1/2 diagonal menor = 6÷2=3

Explicación paso a paso:

1/2 diagonal mayor = 3²+ 8² = X²

1/2 diagonal mayor = 9+ 64 = X²

1/2 diagonal mayor = 73 = X²

1/2 diagonal mayor = raiz de 73 = X

1/2 diagonal mayor = 8.5440037453 = X

Diagonal mayor = 2X= 17.0880074906

Area del rombo = diagonal mayor por diagonal menor entre 2

Area del rombo = (17.0880074906 × 6) ÷ 2

Area del rombo = 102.5280449436 ÷ 2

●Área del rombo = 51.2640224718 cm