Question

interpolar tres medios geométricos entre 12 y 192​

Answer 1

Respuesta:

PG={ 12,24,48,96,192}

Explicación:

$an = a1. {(q)}^{(n - 1)} \\ \\ 12. {(q)}^{(5 - 1)} = 192 \\ \\12. {(q)}^{4} = 192 \\ \\ {q}^{4} = \frac{192}{12} \\ \\ {q}^{2} = 16 \\ \\ {q}^{2} ={2}^{4} \\ \\ q = 2 \\ \\ \\ a1 = 12 \\ \\ a2 =2.(12) = 24 \\ \\ a3 = 2.(24) = 48 \\ \\ a4 = 2.(48) =96 \\ \\a 5 =2.(96) = 192$