Question

(senx+cosx)^2/senx.cosx=2+secx.cscx

Answer 1

Buenas noches;
(sen x+ cosx)²/(sen x.cosx)=(sen²x+2senx. cosx+cos²x) / (sen x.cosx)=
=(1+2.senx.cosx)/ (senx.cosx)=
=(1/ (senx.cox))  + (2senx. cos x) / (senx.cosx)=
=(1/senx).(1/cosx)+2=
=2+csc x.sec x=
=2+sec x.csc x

Un saludo.