Question

¿Cual es la solucion a cada caso?

Answer 1

a) $\frac{2^{3}.2^{5}}{2^{6} } =\frac{2^{3+5}}{2^{6}}= \frac{2^{8}}{2^{6}}=2^{8-6}=2^{2}=4$

b) $\frac{6^{3}.6^{7}}{6^{4}.6^{6} } =\frac{6^{3+7}}{6^{4+6}}= \frac{6^{10}}{6^{10}}=1$

c) $\frac{5^{3}.5^{-2}}{5^{8}.5^{7} } =\frac{5^{3-2}}{5^{8+7}}= \frac{5^{1}}{5^{15}}=5^{1-15}=5^{-14}$

d) $\frac{8^{9}.8^{-2}}{8^{10}.8^{-8} } =\frac{8^{9-2}}{8^{10-8}}= \frac{8^{7}}{8^{2}}=8^{7-2}=8^{5}$