Question

Ayuda porfa es urgente

Answer 1

Solo ten en cuenta que:

${x}^{2} + 2xy + {y}^{2} = {(x + y)}^{2}$

...

$\sqrt{a + b + 2 \sqrt{ab} } = \sqrt{a} + \sqrt{b} \\ \sqrt{ { \sqrt{a} }^{2} + 2 \sqrt{a} \sqrt{b} + { \sqrt{b} }^{2} } = \sqrt{a} + \sqrt{b} \\ \sqrt{ { (\sqrt{a} + \sqrt{b}) }^{2} } = \sqrt{a} + \sqrt{b} \\ \sqrt{a} + \sqrt{b} = \sqrt{a} + \sqrt{b}$