Question

me podeis hacer estos ejercicios rapido porfa
a) (5^3)^4: (5^3)^4 b) 3^-1+3`-2+3^-2+3^-4 c)2^-2:2^-3+4^4 d)(1/5)^0+(1/5)^-1+(1/5)^-2+(1/5)^-3+(1/5)^-4 e) (2/3)^+(2/3)^-2 f) (-2/3)^2-(-2/3)^-2

PORFA HACERLO YAAAA

Answer 1

Explicación paso a paso:

a) (5^3)^4: (5^3)^4 = 5^12 / 5^12 = 1

b) 3^-1 + 3`-2 + 3^-2 + 3^-4 =

1/3 + 1/( 3^2) + 1/( 3^2) + 1/3^4 =

1/3 + 1/9 + 1/9 + 1/3 ^4 = 1/3 + 2/9 + 1/81

= (27 + 18+ 1)/81 = 46/81

c) 2^-2 : 2^-3 + 4^4 = 1/4 : 1/8 + 256 = 8/4 +256

= 2 + 256 = 258

d)(1/5)^0 + (1/5)^-1 + (1/5)^-2 + (1/5)^-3 + (1/5)^-4=

1 +5 + 25 + 125 + 625 = 781

e) (2/3)^ +( 2/3)^-2 = 2/3 + (3/2)^2

= 2/3 + 9/4 = (8 + 27)/4 = 35/4

f) (-2/3)^2 - (-2/3)^-2 = 4/9 - 9/4 = (16 - 81)/ 36

= -65/ 36