Question

Resolucion general de triángulo oblicuángulo segundo caso a= 41
b=19.5
c=32.48

Answer 1

cos A = (b² + c² - a²)/2bc 
cos A = ((19.5)² + (32.48)² - (41)²)/2(19.5)(32.48) 
cos A = (380.25 + 1054.9504 - 1681)/1266.72 
cos A = -245.7996/1266.72 
cos A = -0.1940441455097 
A = 101.188890648821º 

cos B = (a² + c² - b²)/2ac 
cos B = ((41)² + (32.48)² - (19.5)²)/2(41)(32.48) 
cos B = (1681 + 1054.9504 - 380.25)/2663.36 
cos B = 2355.7004/2663.36 
cos B = 0.8844844106692 
B = 27.811860663574º 

cos C = (a² + b² - c²)/2ab 
cos C = ((41)² + (19.5)² - (32.48)²)/2(41)(19.5) 
cos C = (1681 + 380.25 - 1054.9504)/1599 
cos C = 1006.2996/1599 
cos C = 0.6293305816135 
C = 50.9992486876112º