Question

ayuda plis doy 75 puntos

Answer 1

$E=\sqrt[4\times 4]{1+3(2^2+1)(2^4+1)(2^8+1)}\\\\E=\sqrt[16]{1+(2^2-1)(2^2+1)(2^4+1)(2^8+1)}\\\\E=\sqrt[16]{1+(2^4-1)(2^4+1)(2^8+1)}\\\\E=\sqrt[16]{1+(2^8-1)(2^8+1)}\\\\E=\sqrt[16]{1+(2^{16}-1)}\\\\E=\sqrt[16]{2^{16}}\\\\\boxed{\boxed{E=2}}$