Question

2. Reemplaza los valores correspondientes de “a” (3) “b” (-2) y “c” (-3), y calcula:

a) a + b – c = 3 + 2- (-3) =


b) a – b + c = 3 – (-2) + -3 =


c) a + 2b – 2c =


d) 7b : (b + c) =


e) a ∙ c + 2b – 2c =


f) c • (b – a) =

Answer 1

a) a+b-c=3+2-(-3)

(3)+(-2)-(-3)=3+2-(-3)

3-2+3=3+2+3

R/ 4=8

b). a-b+c=3-(-2)+(-3)

(3)-(-2)+(-3)=3-(-2)+(-3)

3+2-3=3+2-3

R/ 2=2

c). a+2b-2c

(3)+2(-2)-2(-3)

3-4+6

R/. 5

d) 7b:(b+c)

7(-2):(-2+(-3))

-14:(-2-3)

R/ -14:6

e). a.c+2b-2c

(3).(-3)+2(-2)-2(-3)

-9-4+6

R/ -7

f). c.(b-a)

(-3).(-2-(3))

(-3).(-2-3)

-3.-5

R/15