Question

Reducir
(x-3)(x+3)(x²+3x+9)(x²-3x+9)-(x³-27)²+1458

Answer 1

Respuesta:

(x-3)(x+3)(x²+3x+9)(x²-3x+9)-(x³-27)²+1458

(x²-9)(x²+3x+9)(x²-3x+9)-(x³-27)²+1458

(x²-9)(x²+3x+9)(x²-3x+9)- $( x^{3*2} -2*27*x^{3}+27^{2} )$ +1458

(x²-9)(x²+3x+9)(x²-3x+9)- $( x^{6} -54x^{3} +729 )$ +1458

$\left(x^4+3x^3-27x-81\right)\left(x^2-3x+9\right)- ( x^{6} -54x^{3} +729 )+ 14 58$

$x^6-729-\left(x^6-54x^3+729\right)+1458$

$x^6-729-x^6+54x^3-729+1458$

$x^6-x^6+ 54x^3-729-729+1458\\\\x^6-x^6+ 54x^3-1458+1458\\\\54x^3$