Question

Si ABC + DEF = 1000, donde A,B,C,D,E y F son cifras, todas ellas distintas de cero, entonces A+B+C+D+E+F es igual a ...

Answer 1

F + C = 10

B+E+1 = 10 ==> B+E = 9
D+A +1 = 10 ==> D+A = 9

o sea A+B+C+D+E+F = (F+C) +(B+E) + (D+A) = 10 + 9 + 9 = 28