Question

En un triángulo ABC (B=90), reduce J. J=(sec2c- cot2A)(Sen2C+ Sen2A)

Answer 1

Respuesta:

$j = (( \frac{b}{a} {)}^{2} - ( \frac{c}{a} {)}^{2} )(( \frac{c}{b} {)}^{2} + ( \frac{a}{b} {)}^{2} ) \\ j = ( \frac{ {b}^{2} - {c}^{2} }{ {a}^{2} } )( \frac{ {c}^{2} + {a}^{2} }{ {b}^{2} } ) \\ j = ( \frac{ {a}^{2} }{ {a}^{2} } )( \frac{ {b}^{2} }{ {b}^{2} } ) \\ j = 1$