Question

Ayudenme por favor .
Con resolucion

Answer 1

Respuesta:

$\frac{(2^{\frac{3}{2} }) }{(2^2)(\sqrt[2]{2}) } }=\frac{(\sqrt[2]{2}) }{(2)(\sqrt[2]{2}) }=\frac{1}{2}$.

Explicación paso a paso:

$(\frac{(4^{\frac{1}{6}})(4^{\frac{1}{4} })(4^{\frac{1}{3} }) }{(4)(4^{\frac{1}{5} })(4^{\frac{1}{20} }) })=(\frac{(4^{\frac{1}{6}+\frac{1}{4}+\frac{1}{3} }) }{(2^{2})((2^{2})^{\frac{1}{5}+\frac{1}{20} }) }=(\frac{((2^{2})^{\frac{1}{6}+\frac{1}{4}+\frac{1}{3} }) }{(2^{2} )(2^{\frac{1}{2} }) })=\frac{(2^{\frac{3}{2} }) }{(2^2)(\sqrt[2]{2}) } }=\frac{(\sqrt[2]{2}) }{(2)(\sqrt[2]{2}) }=\frac{1}{2}$.