Question

Hallar "x" en :
(x-3)(x-4)-2(x-5)=(x-1) al cuadrado ​

Answer 1

Respuesta:

x=3

Explicación paso a paso:

$x^{2} -9x+22=x^{2} -2x+1\\x^{2} -9x+22-22=x^{2} -2x+1-22\\x^{2} -9x=x^{2}-2x-21\\ x^{2} -9x-(x^{2} -2x)=x^{2} -2x-21-(x^{2} -2x)\\\\-7x=-21\\\\\frac{-7x}{-7} =\frac{-21}{-7} \\x=3$