Question

me pueden dar la comprobación de estas ecuaciones porfa   

6(7-x)=8(6-x)
-8(10-x)=-6
(x+2)*3=(13-x)*4+3
3(1-2x)+12=10-2(x-3)

Answer 1

$6(7-x)=8(6-x) \\ \\ 42-6x=48-8x \\ \\ -6x+8x=48-42 \\ \\ 2x=6\to x= \frac{6}{2}\to \boxed{x=3} \\ \\ Comprobacion \\ \\ 6(7-x)=8(6-x)\to 6(7-3)=8(6-3)\to 6(4)=8(3)\to \boxed{24=24} \checkmark$

$-8(10-x)=-6 \\ \\ -80+8x=-6\\ \\ 8x=-6+80 \\ \\ 8x=74 \to x= \frac{74}{8}\to \boxed{x=9,25} \\ \\ Comprobacion \\ \\ -8(10-x)=-6\to -8(10-9,25)=-6\to -8(0,75)=-6\\\to \boxed{-6=-6}\ \checkmark$

$(x+2)*3=(13-x)*4+3 \\ \\ 3x+6=52-4x+3 \\ \\ 3x+4x=52+3-6 \\ \\ 7x=49\to x= \frac{49}{7}\to \boxed{x=7} \\ \\ Comprobacion \\ \\ (x+2)*3=(13-x)*4+3\to (7+2)*3=(13-7)*4+3\to \\ (9)*3=(6)*4+3\to 27=24+3\to \boxed{27=27}\ \checkmark$

$3(1-2x)+12=10-2(x-3) \\ \\ 3-6x+12=10-2x+6 \\ \\ 3+12-10-6=-2x+6x \\ \\ -1=4x\to \boxed{-\frac{1}{4}=x } \\ \\ Comprobacion\\ \\ 3(1-2x)+12=10-2(x-3)\to 3(1-2(- \frac{1}{4}))+12=10-2(- \frac{1}{4}-3) \\ \\ \to 3(1+ \frac{1}{2}))+12=10-2(- \frac{13}{4}) \to 3(\frac{3}{2}))+12=10+ \frac{13}{2} \\ \\ \to \frac{9}{2}+12= \frac{20+13}{2} \to \frac{9+24}{2}= \frac{20+13}{2} \to \boxed{ \frac{33}{2}= \frac{33}{2}}\ \checkmark$

Espero que te sirva, salu2!!!!