Question

($(\frac{1}{2})^{-1}+(\frac{1}{4})^{-2}$

Answer 1

Explicación paso a paso:

$(\frac{1}{2} ^{-1}) + (\frac{1}{4} )^{-2}$

$=(\frac{1}{2^{-1} } ) + (\frac{1}{4^{-2}})$

$=(1 )*( 2^{1}) +(1)*(4^{2})$

$=(1)*(2) + (1)*(16)$

$=2+16$

$= 18$