Question

aplicar las propiedades de la potenciación y resolver a) x.x.x=27 b) x2.x2=16 c) x4:4=216 d)(x2) 3=64

Answer 1

x.x.x = 27
x¹⁺¹⁺¹ = 27
x³ = 27
x³ = 3³
x = 3

x² . x² = 16
x²⁺² = 16
x⁴ = 16
x⁴ = 2⁴
x = 2

(x²)³ = 64
x⁶ = 64
x⁶ = 2⁶
x = 2