Question

Metodo de sustitución
7+4y= 13
5x+2y=19

Answer 1

Respuesta:

4y = 13 - 7

4y = 6

y = 6/4

5x + 2y = 19

Reemplazando "y"

5x + 2(6/4) = 19

Multiplicando todo por 4

20x + 12 = 38

20x = 26

x = 26/20

Answer 2

SOLUCIÓN

♛ HØlα!! ✌

                    $Despejaremos\:"x"\:de\:la\:primera\:ecuaci\'on\\\\7x+4y=13\\\\\\7x=13-4y\\\\\\x=\dfrac{13-4y}{7}\\\\\\Reemplazamos\:x\:en\:la\:segunda\:ecuaci\'on\\\\\\5x+2y=19\\\\\\(5)\left(\dfrac{13-4y}{7}\right)+2y=19\\\\\\\dfrac{(5)(13-4y)+[(7)(2y)]}{7}=19\\\\\\(65-20y)+(14y)=(19)(7)\\\\\\65-6y=133\\\\\\-6y=68\\\\\\y=\dfrac{68}{-6}\\\\\\\boxed{\boldsymbol{y=-11.3333}}$

                     $Reemplazamos\:"y"\:en\:"x"\\\\\\x=\dfrac{13-4y}{7}\\\\\\x=\dfrac{13-4(-11.3333)}{7}\\\\\\x=\dfrac{13+45.3333}{7}\\\\\\x=\dfrac{58.3333}{7}\\\\\\\boxed{\boldsymbol{x=8.33333}}$