Question

PROBLEMA RETADOR -RT EN ÁNGULOS EN POSICIÓN NORMAL

Answer 1

AB = B - A = (6,4) - (-10,12) = (16,-8)

AB = 4AM

(16,-8) =4(M - A)

M - A = (4,-2)

M = (4, -2) + (-10, 12)

M = (-6,10) = |M| (cos θ, sin θ)

2√34 (cos θ, sin θ) = (-6,10)

(cos θ, sin θ) = (-3/√34 , 5/√34)

sin θ cos θ = -15/34