Question

(x + 1)+(x + 2)+ (x + 3) + … + (x + 13) = 132

Answer 1

Respuesta:

x = 41/13

Aproximadamente es:

x = 3,153846....

Explicación paso a paso:

Resolver:

(x + 1)+(x + 2)+ (x + 3) + … + (x + 13) = 132

x+x+x+....x+ 1+2+3+.....13 = 132

13x + 1+2+3+...13 = 132

Recordar que:

$1+2+3+...+n=\frac{n(n+1)}{2}$

Entonces:

$13x +( 1+2+3+...13) = 132$

$13x + (\frac{13(13 + 1)}{2})= 132$

$13x + (\frac{13(14)}{2})= 132$

$13x + \frac{182}{2}= 132$

$13x + 91 = 132$

$13x = 132 - 91$

$13x = 41$

$x = \frac{41}{13}$