Question

$\frac{x+2}{x^{3} -1 } - \frac{1}{x-1}$
Procedimiento

Answer 1

$\frac{x + 2}{x {}^{3} - 1 } - \frac{1}{x - 1}$

desarrollando el cubo de un binomio

$\frac{x + 2}{(x - 1)(x {}^{2} + x + 1)} - \frac{1}{x - 1}$

$\frac{x + 2 - x {}^{2} - x - 1 }{(x - 1)(x {}^{2} + x + 1) }$

$\frac{ - (x {}^{2} - 1)}{(x - 1)(x { + x + 1)}^{} }$

$\frac{ - (x - 1)(x + 1)}{(x - 1)(x {}^{2} + x + 1) }$

simplificando:

Respuesta

$- \frac{x + 1}{x {}^{2} + x + 1}$