Question

simplifica:
$j = \frac{ {3}^{x - 1} + {3}^{ x - 2} } { {3}^{x - 1} - {3}^{x - 3} } =$
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Answer 1

$j = \frac{3 {}^{x - 1} + 3 {}^{x - 2} }{3 {}^{x - 1} - 3 {}^{x - 3} }$

$j = \frac{3 {}^{x}(3 {}^{ - 1} + 3 { }^{ - 2}) }{3 {}^{x} (3 { }^{ - 1} - 3 {}^{ - 3}) }$

$j = \frac{ \frac{1}{3} + \frac{1}{9} }{ \frac{1}{3} - \frac{1}{27} }$

$j = \frac{ \frac{4}{9} }{ \frac{8}{27} }$

$j = \frac{3}{2}$