• Asignatura: Matemáticas
  • Autor: diego980perez
  • hace 9 años

* Racionalizar
* 5/12√3



* 13/√2 - √7

Respuestas

Respuesta dada por: Piscis04
4
 \frac{5}{12 \sqrt{3}}* \frac{ \sqrt{3}}{ \sqrt{3}} =  \frac{5* \sqrt{3}}{12 \sqrt{3}* \sqrt{3}}  \\  \\ \frac{5}{12 \sqrt{3}}* \frac{ \sqrt{3}}{ \sqrt{3}} =  \frac{5* \sqrt{3}}{12 *3\sqrt{3}^2}  \\  \\ \frac{5}{12 \sqrt{3}}* \frac{ \sqrt{3}}{ \sqrt{3}} =  \frac{5* \sqrt{3}}{12 *3}  \\  \\ \frac{5}{12 \sqrt{3}}* \frac{ \sqrt{3}}{ \sqrt{3}} =  \frac{5* \sqrt{3}}{36}=  \boxed{ \frac{5}{36} \sqrt{3}}

 \frac{13}{ \sqrt{2}-  \sqrt{7} }* \frac{ \sqrt{2}+  \sqrt{7}}{ \sqrt{2} + \sqrt{7}} = \\  \\  \frac{13}{ \sqrt{2}-  \sqrt{7} }=  \frac{13*( \sqrt{2}+  \sqrt{7})}{ (\sqrt{2})^2- \sqrt{14}+  \sqrt{14} -( \sqrt{7})^2}  \\  \\  \frac{13}{ \sqrt{2}-  \sqrt{7} }=  \frac{13 \sqrt{2}+13\sqrt{7}}{ (\sqrt{2})^2 -( \sqrt{7})^2} \\  \\  \frac{13}{ \sqrt{2}-  \sqrt{7} }=  \frac{13 \sqrt{2}+13\sqrt{7}}{ 2-7} \\  \\  \frac{13}{ \sqrt{2}-  \sqrt{7} }=  \frac{13 \sqrt{2}+13\sqrt{7}}{ -5}

\frac{13}{ \sqrt{2}-  \sqrt{7} }= \boxed{- \frac{13}{5}  \sqrt{2}- \frac{13}{5} \sqrt{7}  }

Espero que te sirva, salu2!!!!
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