Question

Por favor ayudemen, Las 2 fotos son el mismo ejercicio

Answer 1

$p_{1} +p_{2} +p_{3} =(a+2ab+\frac{1}{2} )+(\frac{2}{3}a+5)+(a-\frac{1}{2}ab+3)\\\\p_{1} +p_{2} +p_{3} =a+\frac{2}{3}a+a+2ab-\frac{1}{2}ab+\frac{1}{2} +5+3\\\\p_{1} +p_{2} +p_{3} =2a+\frac{2}{3}a+\frac{4-1}{2}ab+\frac{1}{2} +8\\\\p_{1} +p_{2} +p_{3} =\frac{6+2}{3}a+\frac{3}{2}ab+\frac{1+16}{2} \\\\p_{1} +p_{2} +p_{3} =\frac{8}{3}a+\frac{3}{2}ab+\frac{17}{2}$

$p_{1} - p_{3} =(a+2ab+\frac{1}{2} )-(a-\frac{1}{2}ab+3)\\\\p_{1} - p_{3} =a+2ab+\frac{1}{2} -a+\frac{1}{2}ab-3\\\\p_{1} - p_{3} =2ab+\frac{1}{2}ab+\frac{1}{2} -3\\\\p_{1} - p_{3} =\frac{4+1}{2}ab+\frac{1-6}{2}\\\\p_{1} - p_{3} =\frac{5}{2}ab-\frac{5}{2}\\\\p_{1} - p_{3} =\frac{5}{2}(ab-1)$