Question

con el procedimiento porfa

Answer 1

Explicación paso a paso:

a)

$3x + \sqrt{16} = {7}^{12} \div {7}^{9} \\ 3x + 4 = {7}^{12 - 9} \\ 3x + 4 = {7}^{3} \\ 3x + 4 = 343 \\ 3x = 339 \\ x = 113$

b)

$6.(3x + 2) + 3.(x + 4) = 108 \\ 18x + 12 + 3x + 12 = 108 \\ 21x + 24 = 108 \\ 21x = 84 \\ x = 4$

c)

$x + \sqrt{ {2}^{3} + {5}^{0} } = {4}^{2} \\ x + \sqrt{8 + 1} = 16 \\ x + \sqrt{9} = 16 \\ x + 3 = 16 \\ x = 13$

d)

$3.y - 15 = \frac{3}{2} . \frac{48}{6} \\ 3y - 15 = \frac{144}{12} \\ 3y - 15 = 12 \\ 3y = 27 \\ y = 9$

e)

$2.(x + 4) - 10 + 5x = 3x + 2 \\ 2x + 8 - 10 + 5x = 3x + 2 \\ 7x - 2 = 3x + 2 \\ 7x - 3x = 2 + 2 \\ 4x = 4 \\ x = 1$