Question

$x^{2} - 2x + 5 = 0$

Answer 1

Respuesta:

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\frac{-\left(-2\right)+\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \:5}}{2\cdot \:1}

\frac{-\left(-2\right)-\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \:5}}{2\cdot \:1}

x=1+2i,\:x=1-2i

Saludos :3