Question

Ayuda para resolver
Necesito operaciones

Answer 1

Respuesta:

Teorema de pitagoras

${a}^{2} + {b}^{2} = {c}^{2}$

Por lo tanto

1) b=3,a=4

${4}^{2} + {3}^{2} = {c}^{2} \\ 16 + 9 = {c}^{2} \\ 25 = {c}^{2} \\ 5 = c$

2) a=9,c=15

${9}^{2} + {b}^{2} = {15}^{2} \\ 81 + {b}^{2} = 225 \\ \: \: \: \: \: \: \: \: \: \: {b}^{2} = 144 \\ \: \: \: \: \: \: \: \: \: \: b = 12$

3) b=24,c=30

${a}^{2} + {24}^{2} = {30}^{2} \\ {a}^{2} + 576 = 900 \\ {a }^{2} = 324 \\ a = 18$

4)a=15,b=20

${15}^{2} + {20}^{2} = {c}^{2} \\ 225 + 400 = {c}^{2} \\ 625 = {c}^{2} \\ 25 = c$

5)a=6,c=10

${6}^{2} + {b}^{2} = {10}^{2} \\ 36 + {b}^{2} = 100 \\ {b}^{2} = 64 \\ b = 8$