Question

En una recta se ubican los puntos A, B, C y D, dondf AB= BC/3=CD/2 y AD=4. Halle la BC

Answer 1

Se coloca una constante

$ab = \frac{bc}{3} = \frac{cd}{2} = k$

Entonces

AB= k

BC=3k

CD=2k

|--k--|-----3k----|--2k-|

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A B C D

Si AD = 4

k+3k+2k = 4

6k = 4

k = 2/3

Hallar BC : 3k = 3(2/3) = 2