Respuestas
Respuesta:
V = 0.00002 L de NH3
Explicación:
que volumen ocuparán 80 moles de CO2 en CNPT
aplicar la ley de los gases ideales:
V x P = n x R x T
DATOS:
n = ¿?
V (L)= ¿?
R = 0.0821 (L atm / mol K)
T = 273 K
P = 1 atm
1. calcular masa en g
masa = 0.015 / 1000 = 0.000015 g
2. calcular moles de NH3
n = masa/Mm
Mm NH3 = 17 g/mol
n = 0.000015 g / 17 g/mol
n = 8.823 x 10⁻⁷ moles
3. calcular volumen que ocupa
V = n x R x T
P
V = (8.823 x 10⁻⁷ mol) x 0.0821 (L atm / mol K) x 273 K
1 atm
V = 0.00002 L de NH3
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1 mol ----- 22.4 L
8.823 x 10⁻⁷ mol ----- x
x = 2 X 10⁻⁵ L de NH3