Question

hallar la pendiente de: (3,-2) , (-1,-2)

Answer 1

SOLUCIÓN

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                                 $\mathrm{Recuerda\:que:}\\\\\mathrm{\boxed{m=\dfrac{y-y_o}{x-x_o}}}\\\\\mathrm{Donde}\\\\\mathrm{*(x_{o},y_{o}): Punto\:de\:paso}\\\\\mathrm{* m: Pendiente}\\\\\\Entonces\\\\m=\dfrac{y-y_o}{x-x_o}\\\\\\m=\dfrac{(-2)-(-2)}{(3)-(-1)}}\\\\\\m=\dfrac{0}{4}\\\\\\\boxed{\boxed{\boldsymbol{m=0}}}$