Question

cual es el procedimiento de la ecuacion de sustitucion 5x+2y=1 -3x+3y=5

Answer 1

SOLUCIÓN

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                   $Despejaremos\:"x"\:de\:la\:primera\:ecuaci\'on\\\\5x+2y=1\\\\\\5x=1-2y\\\\\\x=\dfrac{1-2y}{5}\\\\\\Reemplazamos\:x\:en\:la\:segunda\:ecuaci\'on\\\\\\-3x+3y=5\\\\\\(-3)\left(\dfrac{1-2y}{5}\right)+3y=5\\\\\\\dfrac{(-3)(1-2y)+[(5)(3y)]}{5}=5\\\\\\(-3+6y)+(15y)=(5)(5)\\\\\\-3+21y=25\\\\\\21y=28\\\\\\y=\dfrac{28}{21}\\\\\\\boxed{\boldsymbol{y=1.33333}}$

                    $Reemplazamos\:"y"\:en\:"x"\\\\\\x=\dfrac{1-2y}{5}\\\\\\x=\dfrac{1-2(1.33333)}{5}\\\\\\x=\dfrac{1-2.66667}{5}\\\\\\x=\dfrac{-1.66667}{5}\\\\\\\boxed{\boldsymbol{x=-0.333333}}$