Question

(5+3·2÷6-4)·(4÷2-3+6)÷(7-8÷2-2)²
me ayudan porfavor gracias

Answer 1

Respuesta:

$(5 + 3 \times 2 \div 6 - 4)(4 \div 2 - 3 + 6) \div (7 - 8 \div 2 - 2) {}^{2}$

$(5 + 6 \div 6 - 4)(4 \div 2 - 3 + 6) \div (7 - 8 \div 2 - 2) {}^{2}$

$(5 + 1 - 4)(4 \div 2 - 3 + 6) \div (7 - 8 \div 2 - 2) {}^{2}$

$(5 + 1 - 4)(2 - 3 + 6) \div (7 - 8 \div 2 - 2) {}^{2}$

$(5 + 1 - 4)(2 - 3 + 6) \div (7 - 4 - 2) {}^{2}$

$(2)( 2 - 3 + 6) \div (7 - 4 - 2) {}^{2}$

$(2)(5) \div (7 - 4 - 2) {}^{2}$

$(2)(5) \div (1)$

$10 \div 1$

$= 10$