Question

8x+y=8 3x-2y=16 ayuda aaaaaahhhh​

Answer 1

SOLUCIÓN

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                   $Despejaremos\:"x"\:de\:la\:primera\:ecuaci\'on\\\\8x+y=8\\\\\\8x=8-y\\\\\\x=\dfrac{8-y}{8}\\\\\\Reemplazamos\:x\:en\:la\:segunda\:ecuaci\'on\\\\\\3x-2y=16\\\\\\(3)\left(\dfrac{8-y}{8}\right)-2y=16\\\\\\\dfrac{(3)(8-y)+[(8)(-2y)]}{8}=16\\\\\\(24-3y)+(-16y)=(16)(8)\\\\\\24-19y=128\\\\\\-19y=104\\\\\\y=\dfrac{104}{-19}\\\\\\\boxed{\boldsymbol{y=-5.47368}}$

                   $Reemplazamos\:"y"\:en\:"x"\\\\\\x=\dfrac{8-y}{8}\\\\\\x=\dfrac{8-(-5.47368)}{8}\\\\\\x=\dfrac{8+5.47368}{8}\\\\\\x=\dfrac{13.4737}{8}\\\\\\\boxed{\boldsymbol{x=1.68421}}$