Question

3×(4×2-3)-(4+6÷3)
1+(3+6+1)-[4-(6-3×1)-1]
[3+2×(5-3)÷2]+7
8×3÷4÷(10÷2-4)

Answer 1

3 x (4x2-3) - (4+6÷3)

3 x (8-3) - (10÷3)

3 x 5 - 3.3

15 - 3.3 = 11.7

·························

1 + (3+6+1) - (4-(6-3x1)-1)

1 + (9+1) - (4-(3x1)-1)

1 + 10 - (4-3-1)

1 + 10 - (1-1)

1 + 10 - 0 = 11

··························

(3+2x(5-3)÷2)+7

(3+2x2÷2)+7

(5x2÷2)+7

(10÷2)+7

5+7= 12

························

8x3÷4÷(10÷2-4)

8x3÷4÷(5-4)

8x3÷4÷1

24÷4÷1

6÷1= 6

······················

jerarquía de operaciones

1.-raíz cuadrada o exponentes

2.-paréntesis o potencias

3.-divisiones o multiplicaciones

4.-suma o resta